Hi,
I am trying to find out why the value of clkout variable is 'x , From the figure below which variable should I examine next?(s or clk2)
assign clkout = (s==1’b1)? clk1 : clk2
Value of s is X, value of clk1 is 0 and value of clk2 is X
img
Thanks
Hi,
I am trying to find out why the value of clkout variable is 'x , From the figure below which variable should I examine next?(s or clk2)
assign clkout = (s==1’b1)? clk1 : clk2
Value of s is X, value of clk1 is 0 and value of clk2 is X
img
Thanks
In reply to sj1992:
Both signals contribute to clkout being 'x. Only you or the designer would know what the signals should have been.
In reply to dave_59:
Thanks Dave.