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  • Using Ternary operator in SVA for Temporal scenario

Using Ternary operator in SVA for Temporal scenario

SystemVerilog 6745
Using Ternary operator... 1
MICRO_91
MICRO_91
Full Access
234 posts
May 28, 2023 at 4:57 am

Hi All ,
A recent thread invoked interest whether ternary operator can replace if - else .

The example in the thread has consequent in non-temporal context .
I was wondering if ternary operator can replace if-else in temporary context as well :

Consider the following concurrent assertion where the if-else is used in temporal context :

  property  ife ;
    @( posedge clk ) a ##1 ( b || c )[->1 ]  |->  if( b )  ( ##1 d ) else ( ##1 e ) ;  //  Consequent is Temporal due to ##1d and ##1 e
  endproperty

Now when I try using ternary operator :

  property  Ternary ;
    @( posedge clk ) a ##1 ( b || c )[->1 ]  |->  ( b == 1 ) ? ( ##1 d ) : ( ##1 e ) ;  //  Syntax error !!
  endproperty

Any suggestions on how could I resolve the compilation error ? Also can a temporal expression be written using ternary operator ?

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dave_59
dave_59
Forum Moderator
11281 posts
May 30, 2023 at 7:32 am

In reply to MICRO_91:

As I mentioned to you in this reply, There are three layers of assertion expressions: Boolean, sequences, and properties. The ternary operator is part of any Boolean expression, lust like any other logical or arithmetic operator. You cannot have sequence or properties inside a Boolean expression. if/else is an operation on properties.

if (boolean_expression) property_expr;
 
// is equivalent to
 
booloen_expression |-> property_expr;

Note that the if condition only allows a boolean expression for its antecedent while the implication operator allows a sequence expression.

— Dave Rich, Verification Architect, Siemens EDA

MICRO_91
MICRO_91
Full Access
234 posts
May 30, 2023 at 10:09 am

In reply to dave_59:

Quote:
The ternary operator is part of any Boolean expression .You cannot have sequence or properties inside a Boolean expression

Thanks Dave .

Have_A_Doubt
Have_A_Doubt
Forum Access
225 posts
May 30, 2023 at 10:30 am

In reply to dave_59:

Hi Dave ,

One quick question :

if (boolean_expression) property_expr; 
[ OR ]
if (boolean_expression) property_expr1  else  property_expr2 ;

[Q] Why is it mentioned as property expression specifically ? Can't it be a sequence expression ?

In the example on top :

 property  ife ;
   @( posedge clk ) a ##1 ( b || c )[->1 ]  |->  if( b )  ( ##1 d ) else ( ##1 e ) ; 
 endproperty

##1 d and ##1 e are basically sequences , so what makes it a property expression and not a sequence expression ?

dave_59
dave_59
Forum Moderator
11281 posts
May 30, 2023 at 11:06 am

In reply to Have_A_Doubt:

A property can be a sequence, and a sequence can be a boolean. But the reverse is not true.

Just like in the English language. A sentence is a group of words, but some sentences can be one word (Yes. Go. Correct.). A word is a group of letters, but some words are one letter ("I" "a").

— Dave Rich, Verification Architect, Siemens EDA

Have_A_Doubt
Have_A_Doubt
Forum Access
225 posts
June 03, 2023 at 12:24 pm

In reply to dave_59:

Thanks Dave .

I also observed that since if-else operates on property expression :

sequence  seq_if ;
 @( posedge clk0 ) a ##0 if( D ) B ;
endsequence
 
ap:assert  property( seq_if );
 
//  Output :  Compilation Error : "property operator inside sequence definition"

[Q] So basically if-else can only be written within a property block , right ?

dave_59
dave_59
Forum Moderator
11281 posts
June 03, 2023 at 8:29 pm

In reply to Have_A_Doubt:

you can only use property operators/constructs where property expressions are allowed.

— Dave Rich, Verification Architect, Siemens EDA

Have_A_Doubt
Have_A_Doubt
Forum Access
225 posts
September 09, 2023 at 12:09 pm

In reply to dave_59:

Hi Dave ,
I was referring to example in section 16.13.2 of the LRM :

ap1:assert property( @(posedge clk0) if (b) @(posedge clk1) s1 else @(posedge clk2) s2 );

Can I say the equivalent expression for else part is :

( booloen_expression |-> property_expr1 ) or ( ! booloen_expression |-> property_expr2 ) ;

Also since the if-else expression is directly asserted within assert property, how is it that ap1 is evaluated as property_expression and not a sequence_expression ?

When I write : 

 ap2:assert property (  @(posedge clk0) a ##1 b );

How is that ap2 evaluated as sequence_expression and not a property_expression ?

dave_59
dave_59
Forum Moderator
11281 posts
September 10, 2023 at 4:18 pm

In reply to Have_A_Doubt:

Sequences expressions are composed of sequences and boolean expressions which may be joined by sequence operators. All Boolean expressions by themselves can be a sequence expression, but not all sequence expressions may be Boolean expressions.

Property expressions are composed of properties, sequences and boolean expressions which may be joined by property operators. All Sequence expressions by themselves can be a property expression, but not all property expressions may be sequence expressions.

It follows that all Boolean expressions by themselves may be a property but not all property expressions may be Boolean expressions.

— Dave Rich, Verification Architect, Siemens EDA

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