What is 4KB address boundary in AXI protocol?

In reply to S.P.Rajkumar.V:

When I work out the calculation for the valid and invalid incremental burst transfer, I’m finding that they both don’t equal respectively as shown below.

Valid incremental burst transfer:
4080 % 4096 == ( 4080 + (4*3)) % 4096
4080 == 4096

Invalid incremental burst transfer:
8184 % 4096 == ( 8184 + (4*3)) % 4096
4088 == 4

Can you clarify this?
Thanks,
Mark