In reply to to_learn_uvm:
I assume you meant to ask:
logic ternary_out;
logic x=1'bx;
initial ternary_out = (x) ? 1 :0 );
then the result of ternary_out will be 1’bx??
That is correct
In reply to to_learn_uvm:
I assume you meant to ask:
logic ternary_out;
logic x=1'bx;
initial ternary_out = (x) ? 1 :0 );
then the result of ternary_out will be 1’bx??
That is correct