In reply to Prathamesh Shinde:
Using if/else in a constraint is effectively two implications.
srfc_type inside {1, 4} -> route_to_l1 == 1;
!(srfc_type inside {1, 4}) -> route_to_l1 == 0;
Since you are constraining
srfc_type to be 0 using the with clause, then
route_to_l1 must also be 0 according to the second implication.