Treating stand-alone use of function as an implicit VOID cast

In reply to sebastian_z:

These functions all have return values which you are ignoring. The randomize() function returns a 1 if successful and a 0 if not successful. You should always check the return value.

Because you omitted a return type in the other two functions, it is assumed to return a 1-bit value. Since you aren’t checking the return values, you are getting the warning. You should declare those functions as ‘function void xxxx()’