In reply to mi:
The LRM explains how the bins get constructed for this example. Bins sa/sb defines 9 possible transitions. sa will have one bin for hitting any one of those transitions, and sb creates 9 bins for each transition.
In reply to mi:
The LRM explains how the bins get constructed for this example. Bins sa/sb defines 9 possible transitions. sa will have one bin for hitting any one of those transitions, and sb creates 9 bins for each transition.