In reply to dave_59:
In reply to ce_2015:
array1.and() with (item.index >= length_to_compare || item == array2[item.index])
Absolute pure genius!
Your solution made me go look up in the LRM that the .and() method can do alternate "AND"ing operation when you use the with clause to do something other than just AND the elements of the same array together.
Thank you Dave!