In reply to dave_59:
Hi Dave ,
(1) If ‘==’ takes precedence shouldn’t b be constrained to 1 since ( a < 2 ) would return 1 ( due to in-line constraint a == 1 ; )
(2) Also I didn’t get " since any value of b results in the expression being non-zero(true). "
What if I were to change constraint to ::
b == (a<2) ? 0 : 3;
Would the 0 ( since a == 1 ) play any part ?
Thanks .